Question 1070146: Solve the system of equations where x + 4y = 7 and 3x + y = -1 Found 3 solutions by Boreal, Fombitz, Edwin McCravy:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x + 4y = 7 and 3x + y = -1
x=7-4y
3(7-4y)+y=-1
21-12y+y=-1
-11y=-22
y=2
x=7-4(2)=-1
(-1, 2)
check in second equation
-3+2=-1
this was done by substitution, but it can be done by elimination as well.
multiply top by -3
-3x-12y=-21
3x+y=-1
-11y=-22
y=2
Unlike the others, I'd rather not just do your work for you
all the time. So I like to do one just like it, and let you
do your own work. But before I had finished they had already
done it for you.
Here's one exactly like it
Solve either equation for either letter.
I'll solve the first equation for x
x + 5y = 13
- 5y -5y
------------
x = 13-5y
Substitute (13-5y) for x in the other equation:
4x + y = -5
4(13-5y) + y = -5
52 - 20y + y = -5
52 - 19y = -5
-52 -52
----------------
-19y = -57
y = (-57)/(-19)
y = 3
Substitute (3) for y in
x = 13-5y
x = 13-5(3)
x = 13-15
x = -2
Answer: (x,y) = (-2,3)
Now do your exactly the same way, step by step.
Edwin