SOLUTION: A taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of the two ingredients was 617.6 kg. To the nearest tenth of a kilogram, how many k

Algebra ->  Linear-equations -> SOLUTION: A taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of the two ingredients was 617.6 kg. To the nearest tenth of a kilogram, how many k      Log On


   

Question 1066351: A taco contained approximately 1 kg of onion for every 6.6 kg of grilled steak. The total weight of the two ingredients was 617.6 kg. To the nearest tenth of a kilogram, how many kilograms of onions and how many kilograms of grilled beef were used to make the taco?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The ratio of onions to grilled steak is
+1+%2F+6.6+ kg/kg
I can multiply top and bottom by the same number
and the ratio doesn't change
+10%2F66+
+5+%2F+33+
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Let +x+ = kg of onions to make tacos
+617.6+-+x+ = kg of grilled steak to make tacos
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I can say:
+5+%2F+33+=+x+%2F+%28+617.6+-+x+%29+
Multiply both sides by +33%2A%28+617.6+-+x+%29+
+5%2A%28+617.6+-+x+%29+=+33x+
+3088+-+5x+=+33x+
+38x+=+3088+
+x+=+81.3+
and
+617.6+-+81.3+=+536.3+
81.3 kg of onions to make tacos
536.3 kg of grilled steak to make tacos
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check:
+81.3+%2F+536.3+=+5%2F33+
+.1516+=+.1515+
error due to rounding off, I think
OK