Let h = the hundreds digit
Let t = the tens digit
Let u = the units (or ones) digit
a three digit number is equal to 17 times the sum of its digits.
100h+10t+u = 17(h+t+u)
100h+10t+u = 17h+17t+17u
83h-7t-16u = 0
if 198 is added to the number, the digits are interchanged.
100h+10t+u+198 = 100u+10t+h
99h-99u = -198
h-u = -2
the addition of first and third digit is 1 less than middle digit.
h+u = t-1
h-t+u = -1
find the number
Solve this system:
83h-7t-16u = 0
h - u = -2
h- t+ u = -1
You finish.
Edwin