SOLUTION: Find the x-intercept(s) and the coordinates of the vertex for the parabola y=X^2+6x-7

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Question 1063262: Find the x-intercept(s) and the coordinates of the vertex for the parabola y=X^2+6x-7
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The quadratic expression is factorable. If you wanted to use Completing the Square, then the term to add and subtract is 9.

y=x%5E2%2B6x%2B9-7-9
y=x%5E2%2B6x%2B9-16
y=%28x%2B3%29%5E2-16
The vertex is point (-3,-16).


%28x%2B3%29%5E2-16=0
%28x%2B3%29%5E2=16
x%2B3=0%2B-+4
x=-3%2B-+4
The x-intercepts are -7 and +1.