SOLUTION: 1. A boy's age is 10 and his father's is 37. In how many years' time will the father's age be twice as old as his son?
2. Daniel's age is half of David's, and David's age is fou
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-> SOLUTION: 1. A boy's age is 10 and his father's is 37. In how many years' time will the father's age be twice as old as his son?
2. Daniel's age is half of David's, and David's age is fou
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Question 1063041: 1. A boy's age is 10 and his father's is 37. In how many years' time will the father's age be twice as old as his son?
2. Daniel's age is half of David's, and David's age is four times of Salum's now. If in two years' time the sum of their ages will be 55 years, find David's age after four years. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! (1) Let = number of years from
now when father's age is twice son's age
In 17 yrs, father's age is twice son's age
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