SOLUTION: A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of
uniform width. The area of the garden and walkway together is 30 less than twice the
area of
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-> SOLUTION: A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of
uniform width. The area of the garden and walkway together is 30 less than twice the
area of
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Question 1053331: A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of
uniform width. The area of the garden and walkway together is 30 less than twice the
area of the garden. Find the width of the walkway. Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! .
A garden is 15 ft by 13 ft. You are building a walkway around this garden that is of
uniform width. The area of the garden and walkway together is 30 less than twice the
area of the garden. Find the width of the walkway.
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Let "w" be the width of the walkway.
Then the dimensions of the large rectangle are 15+2w and 13+2w.
The area of the large rectangle is the product (15+2w)*(13+2w).
The condition says
(15+2w)*(13+2w) = 2*15*13 - 30.
You need to solve this equation for w. Simplify:
15*13 + 30w + 26w + 4w^2 = 2*15*13 - 30,
4w^2 + 56w = 165,
4w^2 + 56w - 165 = 0.
Use the quadratic formula
= = .
= = = 2.5 ft. (Ignore the negative root).
Answer. 2.5 ft
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