|
Question 1052870: Find the equation of the line that contains the point
P(2, 3)
and is perpendicular to the graph of
y =3/2x-1
Found 2 solutions by Alan3354, Boreal:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Same problem, different numbers
=======================================
Find the equation of the line that contains the point P(-2,0)
and is perpendicular to the graph of y=2/3x-3
--------------
The slope of y = (2/3)x-3 is 2/3
The slope of lines perpendicular is the negative inverse, -3/2
------------
Use  where (x1,y1) is the point.
y-0 = (-3/2)*(x+2)
y = (-3/2)*(x+2)
Answer by Boreal(15235)  (Show Source):
You can put this solution on YOUR website! Two lines that are perpendicular have a slope product that is the negative reciprocal, or -1.
y=(3/2)x-1 has a slope of 3/2
To find the negative reciprocal, flip the fraction and change the sign. The negative reciprocal is -2/3
Now use the point slope formula where
y-y1=m(x-x1), where (x1,y1) is the point and m the slope
y-3=(-2/3)(x-2)
y-3=-(2/3)x+(4/3)
3 is 9/3
y=-(2/3)x+13/3 ANSWER
|
|
|
| |
