SOLUTION: Find an equation for the line perpendicular to the line 7x + 14y = −8 having the same y-intercept as x − 5y = −25.

Algebra ->  Linear-equations -> SOLUTION: Find an equation for the line perpendicular to the line 7x + 14y = −8 having the same y-intercept as x − 5y = −25.       Log On


   

Question 1050329: Find an equation for the line perpendicular to the line
7x + 14y = −8 having the same
y-intercept as
x − 5y = −25.
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Slope for the line 7x+14y=-18 is -1%2F2.

A line in the plane perpendicular to that one will have slope 2;
which is the negative reciprocal of the given line.

Finding y-intercept of other given line , x-5y=-25;
-5y=-x-25
y=x%2F5%2B5
y-axis intercept is the point (0,5).


RETURNING TO QUESTION
Find equation of the line with slope 2 and containing as y-intercept the point (0,5).

FIT DIRECTLY INTO SLOPE-INTERCEPT FORM
highlight%28highlight%28y=2x%2B5%29%29