SOLUTION: I need to write an equation in slope intercept form for the line that passes through the given point and is Perpendicular to the graph of the given equations. I need to show work.

Algebra ->  Linear-equations -> SOLUTION: I need to write an equation in slope intercept form for the line that passes through the given point and is Perpendicular to the graph of the given equations. I need to show work.       Log On


   

Question 1048453: I need to write an equation in slope intercept form for the line that passes through the given point and is Perpendicular to the graph of the given equations. I need to show work. (-2,-2),y=-1/3x=9
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
Line thru(-2,-2),perpendicular to y=-1/3x+9 , m = (-1/3)
Perpendicular Line m = 3/1 (negative reciprocal of (-1/3))
Using point-slope form, y+-+y%5B1%5D+=+highlight_green%28m%29%28x+-+x%5B1%5D%29
y + 2 = 3(x+2)
y = 3x + 4 (in slope intercept form)