SOLUTION: Romeo and Juliet saw each other when they were 270 ft. apart. Romeo ran to Juliet at a rate of 16 ft/second. At the same moment, Juliet ran to Romeo at a rate of 14 ft/second. 1

Algebra ->  Linear-equations -> SOLUTION: Romeo and Juliet saw each other when they were 270 ft. apart. Romeo ran to Juliet at a rate of 16 ft/second. At the same moment, Juliet ran to Romeo at a rate of 14 ft/second. 1      Log On


   

Question 1047987: Romeo and Juliet saw each other when they were 270 ft. apart. Romeo ran to Juliet at a rate of 16 ft/second. At the same moment, Juliet ran to Romeo at a rate of 14 ft/second.
1) How many seconds after they started running will they meet?
2) How far will Romeo have to run then?
135+16x=135+14x
Please help I am so confused.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +d+ = the distance in feet that
Romeo has to run until they meet
+270+-+d+ = the distance in feet that
Juliet has to run until they meet
Let +t+ = time in seconds until they meet
-----------------------------------------
Romeo's equation:
(1) +d+=+16t+
Juliet's equation:
(2) +270+-+d+=+14t+
-------------------------
Substitute (1) into (2)
(2) +270+-+16t+=+14t+
(2) +30t+=+270+
(2) +t+=+9+
--------------------------
They will meet in 9 sec
------------------------
(1) +d+=+16t+
(1) +d+=+16%2A9+
(1) +d+=+144+
-------------------
I don't get this 2nd part. It says
" How far will Romeo have to run then?"
Does that mean AFTER they meet?
He runs 144 ft UNTIL they meet
Then he runs +270+-+144+=+126+ ft
to get to where Juliet started.
It's kind of strange wording