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Question 1044180: An executive invests $30,000, some at 10% and some at 5%. If she receives an annual return of $2,200, how much is invested at 10%?
Found 2 solutions by jorel555, ikleyn:
Answer by jorel555(1290)   (Show Source):
You can put this solution on YOUR website! Let n be the amount invested at 10%. Then:
.1n+.05(30000-n)=2200
.1n+1500-.05n=2200
.05n=700
n=700/.05=14000
$14000 was invested at 10%, $16000 was invested at 5%. ☺☺☺☺
Answer by ikleyn(52788)  (Show Source):
You can put this solution on YOUR website! .
An executive invests $30,000, some at 10% and some at 5%. If she receives an annual return of $2,200, how much is invested at 10%?
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1. Solution with two unknowns
Let t be an amount invested at 10%, and f be an amount invested at 5%. Then you have these to equations
t + f = 30000,
0.1t + 0.05f = 2200.
You can solve it by the substitution method or by the elimination method.
2. Solution with one unknown
Then your equation is
0.1t + 0.05*(30000-t) = 2200, or
0.1t + 5*300 - 0.05t = 2200, or
0.05t = 2200-1500, or
0.05t = 700, t =  = 14000.
Answer. 14000 invested at 10%, 16000 invested at 5%.
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