SOLUTION: The cost of developing pictures is a linear function of the number of pictures ordered. We placed two orders. The first order had 50 pictures and cost $3.75. The second order had

Algebra ->  Linear-equations -> SOLUTION: The cost of developing pictures is a linear function of the number of pictures ordered. We placed two orders. The first order had 50 pictures and cost $3.75. The second order had      Log On


   



Question 1043717: The cost of developing pictures is a linear function of the number of pictures ordered. We placed two orders. The first order had 50 pictures and cost $3.75. The second order had 54 pictures and cost $3.95. Find the cost as a function of the number of pictures
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
You are given two points on the line:
( 50,3 )
( 54,3.95 )
Let +C+=+f%28n%29+ where +C+ is cost
and +n+ is the number of pictures ordered
--------------------------------------
Use the general point-slope formula
+%28+C+-+3+%29+%2F+%28+n+-+50+%29+=+%28+3.95+-+3+%29+%2F+%28+54+-+50+%29+
++%28+C+-+3+%29+%2F+%28+n+-+50+%29+=+.95+%2F+4+
Multiply both soides by +4%2A%28+n+-+50+%29+
+4%2A%28+C+-+3+%29+=+.95%2A%28+n+-+50+%29+
+4C+-+12+=+.95n+-+47.5+
+4C+=+.95n+-+35.5+
+C+=+.2375n+-+8.875+
-----------------------
check:
( 50,3 )
+C+=+.2375n+-+8.875+
+3+=+.2375%2A50+-+8.875+
+3+=+11.875+-+8.875+
+3+=+3+
------------------------
( 54, 3.95 )
+C+=+.2375n+-+8.875+
+3.95+=+.2375%2A54+-+8.875+
+3.95+=+12.825+-+8.875+
+3.95+=+3.95+
OK