SOLUTION: What is the equation of the line perpendicular to 5x+2y-1=0 that goes through (-2,4)

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Question 1027997: What is the equation of the line perpendicular to 5x+2y-1=0 that goes through (-2,4)
Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the equation of the line perpendicular to 5x+2y-1=0 that goes through (-2,4)
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Find the slope of the given line.
The slope of lines perpendicular is the negative inverse.
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Then use y-y1 = m*(x-x1) where m = slope and (x1,y1) is the point (-2,4)

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Perpendicular lines have slopes that are negative reciprocals.
5x%2B2y-1=0
2y=-5x%2B1
y=-%285%2F2%29x%2B1%2F2
So,
-%285%2F2%29%2Am%5Bp%5D=-1
m%5Bp%5D=2%2F5
Using the point-slope form,
y-4=%282%2F5%29%28x%2B2%29
5y-20=2x%2B4
-2x%2B5y-24=0
2x-5y%2B24=0
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