SOLUTION: A line has equation ln(y) = a ln(x) + b where a = 0.688 and b = 3.524. The equation can be written in the form y = cx^d What is the value of c, to 2 decimal places?

Algebra ->  Linear-equations -> SOLUTION: A line has equation ln(y) = a ln(x) + b where a = 0.688 and b = 3.524. The equation can be written in the form y = cx^d What is the value of c, to 2 decimal places?      Log On


   



Question 1024920: A line has equation
ln(y) = a ln(x) + b
where a = 0.688 and b = 3.524. The equation can be written in the form
y = cx^d
What is the value of c, to 2 decimal places?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+ln%28y%29+=+a%2Aln%28x%29+%2B+b+
+ln%28y%29+=+.688%2Aln%28x%29+%2B+3.524+
---------------
If +e%5E3.524+=+33.92+, then
+3.524+=+ln%28+33.92+%29+, so
+ln%28y%29+=+.688%2Aln%28x%29+%2B+ln%28+33.92+%29+
+ln%28y%29+=+ln%28+x%5E.688+%29+%2B+ln%28+33.92+%29+
+ln%28y%29+=+ln%28+33.92%2Ax%5E.688+%29+
+y+=+33.92%2Ax%5E.688+
--------------------
+c+=+33.92+