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Question 1024838: Hi, can someone check my answers? Thanks!
Find the equation of the line that contains the point (3,2) and that is:
a) parallel to the line containing the points (3,6) and (6,-9)
I got the answer y=-5x+17 by finding the slope first and then substituting the points (3,2) into the y=mx+b equation and solving for b.
b) perpendicular to the line containing the points (3,6) and (6,-9)
So the equation is the same as above except for the slope and I ended up getting y=-1/5x+13/5.
How does that look?
Found 2 solutions by josgarithmetic, MathTherapy: Answer by josgarithmetic(39617) (Show Source): Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
Hi, can someone check my answers? Thanks!
Find the equation of the line that contains the point (3,2) and that is:
a) parallel to the line containing the points (3,6) and (6,-9)
I got the answer y=-5x+17 by finding the slope first and then substituting the points (3,2) into the y=mx+b equation and solving for b.
b) perpendicular to the line containing the points (3,6) and (6,-9)
So the equation is the same as above except for the slope and I ended up getting y=-1/5x+13/5.
How does that look?
"a" is correct. Good job!
However, "b" is:
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