SOLUTION: Hello Tutors,
I need to find the equation of a line perpendicular to y=-5 and through the point (14,-14). I need to show my work. Can someone explain in laymen's terms?
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-> SOLUTION: Hello Tutors,
I need to find the equation of a line perpendicular to y=-5 and through the point (14,-14). I need to show my work. Can someone explain in laymen's terms?
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Question 1017228: Hello Tutors,
I need to find the equation of a line perpendicular to y=-5 and through the point (14,-14). I need to show my work. Can someone explain in laymen's terms? Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! y=-5 is a horizontal line.
A perpendicular line must therefore have a constant x-value. That line may have any value for y so long as the x-value is constant.
The point given is (14,-14). The x-value given is 14. That is the equation of the line perpendicular to y=-5. It is x=14. There is no y in the equation. All that matters is that x=14. That line will go through the point and be perpendicular to y=-5.
