SOLUTION: a. Is the point (-1, 1) on the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0 ? Show work. b. Find the x and y intercepts for the graph of 〖(x-1)&#123

Algebra ->  Linear-equations -> SOLUTION: a. Is the point (-1, 1) on the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0 ? Show work. b. Find the x and y intercepts for the graph of 〖(x-1)&#123      Log On


   

Question 1015646: a. Is the point (-1, 1) on the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0 ?
Show work.



b. Find the x and y intercepts for the graph of 〖(x-1)〗^2+〖(y-3)〗^2=0
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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A).
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It is difficult to discern your equation.
If this is not your equation, clarify it and re-post your question.
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%28x-1%29%5E2%2B%28y-3%29%5E2=0
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Point (-1,1)
x=-1, y=1
Put these values in the equation, and evaluate to see if it is true.
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%28%28-1%29-1%29%5E2%2B%281-3%29%5E2=0
-2%29%5E2%2B%28-2%29%5E2=0
4%2B4=0
8=0 . False. The point is not on the graph.
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B).
x intercept: y=0
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%28x-1%29%5E2%2B%28y-3%29%5E2=0
%28x-1%29%5E2%2B%280-3%29%5E2=0
%28x-1%29%5E2%2B%28-3%29%5E2=0
%28x-1%29%5E2%2B9=0
%28x-1%29%5E2=-9
sqrt%28%28x-1%29%5E2%29=sqrt%28-9%29
x-1=+/-3i
x=1%2B3i OR x=1-3i
No x intercept.
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y intercept: x=0
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%28x-1%29%5E2%2B%28y-3%29%5E2=0
%280-1%29%5E2%2B%28y-3%29%5E2=0
%28-1%29%5E2%2B%28y-3%29%5E2=0
1%2B%28y-3%29%5E2=0
y-3%29%5E2=-1
sqrt%28%28y-3%29%5E2%29=sqrt%28-1%29
y-3=+/-i
y=3%2Bi OR y=3-1
No y intercept.
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Graph of the equation is a circle with center at (1,3) and zero radius.
The only real number solution is point (1,3).