SOLUTION: If the left side of an inequality is an absolute value and the right side is not and the sides are separated by a sign indicating "less than" or "less than or equal to", then any s

Algebra ->  Linear-equations -> SOLUTION: If the left side of an inequality is an absolute value and the right side is not and the sides are separated by a sign indicating "less than" or "less than or equal to", then any s      Log On


   



Question 1013267: If the left side of an inequality is an absolute value and the right side is not and the sides are separated by a sign indicating "less than" or "less than or equal to", then any solution that is a compound inequality involves two single inequalities separated by "or".
True or false

Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
False.
Look at an example: |x + 1| < 5
This breaks into
x+1 < 5 and x+1 > -5
x < 4 and x > -6
These overlap...a logical AND case, not an OR case.