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Question 1011208: y+4=-4(x-2)
rewrite this equation in slope-intercept form?
rewrite this equation in standard form?
what is the equation in standard form of perpendicular line that passes through(5,1)
what is the x-intercept of the perpendicular line
thank you
Answer by rothauserc(4718)   (Show Source):
You can put this solution on YOUR website! y +4 = -4(x-2)
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slope intercept form
y = -4x +8 -4
y = -4x +4
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standard form
4x +y = 4
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slope of line is -4
slope of perpendicular line is 1/4 (this is the negative reciprocal of the line's slope)
y = x/4 + b
now use the point (5, 1)
1 = 5/4 + b
b = -1/4
y = x/4 - 1/4
-x/4 +y = -1/4
multiply both sides of = by -4
standard form of perpendicular line is
x -4y = 1
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x = 1 +4y
if y=0, then x=1
the x intercept is at x=1 and the point of intersection is (1, 0)
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