SOLUTION: Type a slope-intercept equation of the line that passes through the point (2,-2) and (3,2)

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Question 1006404: Type a slope-intercept equation of the line that passes through the point (2,-2) and (3,2)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (2, -2) and (x2, y2) = (3, 2).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%282--2%29%2F%283-2%29+=+4.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 4%2A2+%2Bb+=+-10. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=-2-4%2A2+=+-10.

y=(4)x + (-10)

Your graph:





so, your equation is: y=4x+-10