SOLUTION: Five years ago, a mother was twice as old as her son. In 6 years time the sum of their ages will be 82. Find their present ages.
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-> SOLUTION: Five years ago, a mother was twice as old as her son. In 6 years time the sum of their ages will be 82. Find their present ages.
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Question 1000089: Five years ago, a mother was twice as old as her son. In 6 years time the sum of their ages will be 82. Find their present ages. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Five years ago, a mother was twice as old as her son. In 6 years time the sum of their ages will be 82. Find their present ages.
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The sum now is 82 - 12 = 70
The sum 5 years ago was 70 - 10 = 60
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--> 5 yrs ago they were 20 & 40.
