SOLUTION: find the x- and y- intercepts of the line that passes through the given points. (-5,-5),(4,-2). Your help is greatly appreciated, thank you!

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Question 1000053: find the x- and y- intercepts of the line that passes through the given points. (-5,-5),(4,-2). Your help is greatly appreciated, thank you!

Found 3 solutions by josgarithmetic, MathTherapy, cinnholmes:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The line's equation is x-3y=10 in standard form. You fill in the steps.

Find the axis intercepts this way:
Let x=0 and find y. This is the y-intercept.
Let y=0 and find x. This is the x-intercept.

An example demonstration how to find the equation for the line containing two given points is shown in this video: how to find equation of a line using two specific given points

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
find the x- and y- intercepts of the line that passes through the given points. (-5,-5),(4,-2). Your help is greatly appreciated, thank you!
Determine the equation of the line first, by using the point-slope formula: y+-+y%5B1%5D+=+%28%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29%29%28x+-+x%5B1%5D%29
When the equation is determined, substitute 0 for y to find the x-intercept. Then substitute 0 for x to find the y-intercept
[Hint]: Slope, or m = 1%2F3

Answer by cinnholmes(1) About Me  (Show Source):
You can put this solution on YOUR website!
the solution is :
Solve for X :
x= 1/3y+10
10+1/3y=x
10+1/3(0)=x
x=10
Solve for Y :
y= 1/3x + -10/3
-10/3 + 1/3x =y
-10/3 + 1/3(0)
Y= -10/3