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Tutors Answer Your Questions about Length-and-distance (FREE)
Question 1151508: standard stop sign is 75cm across from one side of the red octagon to the opposite side, with a 2-cm white border, using a scale of 14, the ENTIRE width of an image of the stop sign is _____cm. the width of the INSIDE red portion is ______cm
Click here to see answer by MathLover1(20849)   |
Question 1151650: You are working at aa pizza delivery store and someone calls in a special order. They want a large pizza (15 inches in diameter) but only want 1/10 of the pizza to have pepperoni. What is the area of the slice of pizza that will have pepperoni?
Click here to see answer by josmiceli(19441)  |
Question 1152481: Two lines, a and b, are parallel. If both of the lines are rotated 90° in the
same direction and then translated to the right by the same number of units,
which statement about the lines resulting from these transformations is true?
A. They will be parallel.
B. They will be the same line.
C. They will be perpendicular.
D. They will intersect, but they won’t be perpendicular.
Click here to see answer by Alan3354(69443)  |
Question 1152563: Imagine that a rope is wrapped tightly around the earth at the equator. Then suppose that the cable is cut, an additional 20 feet are added to the rope, and that this longer rope is put back around the equator, but now it is hovering around the earth with equal space between the rope and the equator. Because the rope is now a little longer than the circumference of the earth, there will be a gap between the rope and the surface of the earth. How large is the gap?
Items for Discussion
● What does this look like? (make sure you and your partner understand the problem, it may help to draw a picture)
● How big do you think the gap is? What’s your guess?
● Do you think you would be able to walk under the rope? Crawl under the rope? Slide your hand under the rope?
The diameter of the Earth at the equator is about 7,926 miles.
Click here to see answer by josgarithmetic(39616) |
Question 1152563: Imagine that a rope is wrapped tightly around the earth at the equator. Then suppose that the cable is cut, an additional 20 feet are added to the rope, and that this longer rope is put back around the equator, but now it is hovering around the earth with equal space between the rope and the equator. Because the rope is now a little longer than the circumference of the earth, there will be a gap between the rope and the surface of the earth. How large is the gap?
Items for Discussion
● What does this look like? (make sure you and your partner understand the problem, it may help to draw a picture)
● How big do you think the gap is? What’s your guess?
● Do you think you would be able to walk under the rope? Crawl under the rope? Slide your hand under the rope?
The diameter of the Earth at the equator is about 7,926 miles.
Click here to see answer by ikleyn(52775)  |
Question 1152849: Find an equation of the straight line passing through the points with coordinates (4, −7)
and (−6, 11), giving your answer in the form ax + by + c = 0,where a, b and c are
integers.
The line crosses the x-axis at point A and the y-axis at point B and O is the origin.
(b) Find the area of triangle AOB.
Click here to see answer by dkppathak(439)  |
Question 1152849: Find an equation of the straight line passing through the points with coordinates (4, −7)
and (−6, 11), giving your answer in the form ax + by + c = 0,where a, b and c are
integers.
The line crosses the x-axis at point A and the y-axis at point B and O is the origin.
(b) Find the area of triangle AOB.
Click here to see answer by Alan3354(69443) |
Question 1153689: Tommy has decided to install a maintenance free fencing on 3 sides of the owners backyard and install a row of hedges forming a natural fence on the 4th side.
The layout is rectangular with a perimeter of 584 feet. The width is 16 feet longer than half the length. Determine the backyards dimensions.
What is the length and width of the yard?
Length in feet=
Width in feet=
Click here to see answer by josgarithmetic(39616) |
Question 1154317: Find the area of the polygons whose vertices are:
a. (-4, 2), (3, -4), (6, 2), (1, 4)
b. (-3, 4), (1, 5), (4, 2), (3, -3), (-2, -4)
Click here to see answer by Edwin McCravy(20054)  |
Question 1154317: Find the area of the polygons whose vertices are:
a. (-4, 2), (3, -4), (6, 2), (1, 4)
b. (-3, 4), (1, 5), (4, 2), (3, -3), (-2, -4)
Click here to see answer by MathTherapy(10551)  |
Question 1154317: Find the area of the polygons whose vertices are:
a. (-4, 2), (3, -4), (6, 2), (1, 4)
b. (-3, 4), (1, 5), (4, 2), (3, -3), (-2, -4)
Click here to see answer by ikleyn(52775) |
Question 1155424: A circular planetary ring of radius 135000 km completes one full revolution in 190000 hours.
a) What is the angular velocity of the ring? (in radians/hour)
b) What is the linear velocity of a rock on the ring? (in km/hr)
Click here to see answer by ikleyn(52775) |
Question 1155608: A playground is being built in the shape of a rectangle with a length of 20 feet and a width of 18 feet. For all calculations involving π, use π≈3.14. How much fencing would need to bought to enclose the playground?
Amount of fencing =
Round answers to 2 decimal places as needed.
Click here to see answer by Alan3354(69443) |
Question 1155608: A playground is being built in the shape of a rectangle with a length of 20 feet and a width of 18 feet. For all calculations involving π, use π≈3.14. How much fencing would need to bought to enclose the playground?
Amount of fencing =
Round answers to 2 decimal places as needed.
Click here to see answer by josgarithmetic(39616) |
Question 1155608: A playground is being built in the shape of a rectangle with a length of 20 feet and a width of 18 feet. For all calculations involving π, use π≈3.14. How much fencing would need to bought to enclose the playground?
Amount of fencing =
Round answers to 2 decimal places as needed.
Click here to see answer by ikleyn(52775) |
Question 1155789: In an art gallery, the curator organized the exhibition. 10 same sized pictures were displayed on the wall. The curator gave 0.5m gap between each picture and put 1.5m distance at both edges of the wall. If each frame is 2.8m long, what is the length (in meters) of the wall?
Click here to see answer by mananth(16946)  |
Question 1155797: Let R be the circle centered at (0,0) with radius 10. The lines x = 6 and y = 5 divide R into four regions R1, R2, R3, and R4. Let R denote the area of region Ri. If R1 > R2 > R3 > R4,then find R1 - R2 - R3 + R4.
Click here to see answer by ikleyn(52775) |
Question 1155836: Let R be the circle centered at (0,0) with radius 10. The lines x=6 and y=5 divide R into four regions R1, R2, R3, and R4.
If the area of R1 is greater than R2 is greater than R3 is greater than R4 then find the area of R1-R2-R3+R4
Click here to see answer by mananth(16946) |
Question 1155932: A spaceship from another planet travels at a speed of 4.4 googs per mulm. There are 256 googs in a plotz and 12.3 plotz in a wraslm. If 3.4 ptock equal one mulm, what is the ship’s speed in wraslm per ptock? Answer in scientific notation to one decimal place.
Click here to see answer by ikleyn(52775) |
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