SOLUTION: A grouo of students walk at 4km/h to an overnight hut. The next day they walk 5km/h back to the start. If the walk from the hut took them 48 minutes less than the walk to the hut,

Algebra ->  Length-and-distance -> SOLUTION: A grouo of students walk at 4km/h to an overnight hut. The next day they walk 5km/h back to the start. If the walk from the hut took them 48 minutes less than the walk to the hut,       Log On


   

Question 973201: A grouo of students walk at 4km/h to an overnight hut. The next day they walk 5km/h back to the start. If the walk from the hut took them 48 minutes less than the walk to the hut, what is the distance between the overnight hut and the start?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +t+ = time in hrs walking to hut
+t+-+48%2F60+ = time in hrs walking back to start
( 48 min is converted to hrs )
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Walking to hut:
(1) +d+=+4t+
Walking back to start:
(2) +d+=+5%2A%28+t+-+48%2F60+%29+
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Substitute (1) into (2)
(2) +4t+=+5%2A%28+t+-+4%2F5+%29+
(2) +4t+=+5t+-+4+
(2) +t+=+4+ hrs
and
(1) +d+=+4t+
(1) +d+=+4%2A4+
(1) +d+=+16+ km
Distance between hut and start is 16 km
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check:
(2) +d+=+5%2A%28+t+-+48%2F60+%29+
(2) +d+=+5%2A%28+4+-+4%2F5+%29+
(2) +d+=+5%2A%28+20%2F5+-+4%2F5+%29+
(2) +d+=+5%2A%28+16%2F5+%29+
(2) +d+=+16+
OK