SOLUTION: The model distance = 3.30+0.235*(speed) can be used to predict the stopping distance (in feet) for a car traveling at a specific speed (in mph). According to this model, about how

Algebra ->  Length-and-distance -> SOLUTION: The model distance = 3.30+0.235*(speed) can be used to predict the stopping distance (in feet) for a car traveling at a specific speed (in mph). According to this model, about how       Log On


   



Question 935399: The model distance = 3.30+0.235*(speed) can be used to predict the stopping distance (in feet) for a car traveling at a specific speed (in mph). According to this model, about how much distance will a car going 65 mph need to stop?
A) 27.0 feet
B)4.3 feet
C) 729.0 feet
D)18.6 feet
E)345.0 feet

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
d = 3.30+0.235*(65)
d = 18.575
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answer:
D)18.6 feet
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