SOLUTION: Graph the triangle with vertics a(0,24), b(-15,0), c(24,0). A) draw the three altitudes. Determine(algebraically) where the three altitudes intersect.

Algebra ->  Length-and-distance -> SOLUTION: Graph the triangle with vertics a(0,24), b(-15,0), c(24,0). A) draw the three altitudes. Determine(algebraically) where the three altitudes intersect.       Log On


   

Question 927664: Graph the triangle with vertics a(0,24), b(-15,0), c(24,0). A) draw the three altitudes. Determine(algebraically) where the three altitudes intersect.
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
BC is the horizontal line y=0 (the x-axis), and AC is the line x%2By=24<--->y=-x%2B24 .
Since BC is the horizontal line y=0 (the x-axis), the altitude to BC is the vertical line passing through A, x=0 (the y-axis).
Since AC is a line with slope=-1 , the altitude to AC is the line with slope=1 passing through B(-15,0).
That line is y-0=1%28x-%28-15%29%29<--->y=x%2B15 .
The three altitudes intersect at one point.
The point where the two altitudes found intersect can be found by solving the system
system%28x=0%2Cy=x%2B15%29--->system%28x=0%2Cy=15%29 .
That intersection is the point (0,15).