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Question 924005: I just want to check if my answer is correct.
Problem: The center of the circle is at (-3,-2). If a chord of length 4 is bisected at (3,1), find the length of the radius.
My answer is: 2√14
Answer by josgarithmetic(39616)   (Show Source):
You can put this solution on YOUR website! I have not yet worked through the question, but I can further describe this:
Point (3,1) is interior of the circle; and because it is bisecting the chord, the chord seems to be perpendicular to the segment from (-3,-2) to (3,1). Draw a sketch or figure of all this on paper. Find the slope of those two points. The slope of the chord is the negative reciprocal of that of (-3,-2) to (3,1). You want equation for the line which contains the chord. You will now have the slope, and you have a point on the chord being the point (3,1); so use point-slope form of a line to find the equation of the line containing the chord....
Knowing (3,1) should be midpoint of the chord, the chord is made of two segments each of 2 unit length. ...
... You should now see a way to use the Distance Formula, for finding point 2 units away from (3,1) on the line of the chord.
Again the reminder, draw the picture and study the description I gave, and you should find how to work through and solve the question.
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