SOLUTION: The width of a rectangle is 5 inches less than 3 times the length.
The area is 2 inches squared. Find the length and width
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Length-and-distance
-> SOLUTION: The width of a rectangle is 5 inches less than 3 times the length.
The area is 2 inches squared. Find the length and width
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You can put this solution on YOUR website! length x
x(3x-5) = 2in^2
3x^2 - 5x - 2 = 0 (Tossing out the negative solution for unit measure)
(3x +1)(x-2)= 0
x = 2in, the length. The width is 1in
and...
A = 2in^2