SOLUTION: Point E is located at (2, −3) and point F is located at (−2, −1). Find the y value for the point that is 3 over 4 the distance from point E to point F.

Algebra ->  Length-and-distance -> SOLUTION: Point E is located at (2, −3) and point F is located at (−2, −1). Find the y value for the point that is 3 over 4 the distance from point E to point F.       Log On


   

Question 863330: Point E is located at (2, −3) and point F is located at (−2, −1). Find the y value for the point that is 3 over 4 the distance from point E to point F.

Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

Midpoint Pt(x,y):  ( %28x%5B1%5D+%2B+x%5B2%5D%29%2F2, %28y%5B1%5D+%2B+y%5B2%5D%29%2F2++%29)

(2, -3) 

(-2, -1) Mpt = (0, -2)

(0, -2)

(-2,-1)  Mpt = (-1,highlight_green%28-1.5%29+)   3/4 Distance from E to F

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
, the translation of the description and question into pure symbols. Distance Formula is used.
%283%2F4%29sqrt%28%284%29%5E2%2B%28-2%29%5E2%29=sqrt%28%28x-2%29%5E2%2B%28y%2B3%29%5E2%29
%283%2F4%29sqrt%2816%2B4%29=sqrt%28%28x-2%29%5E2%2B%28y%2B3%29%5E2%29
%289%2F16%29%2A20=%28x-2%29%5E2%2B%28y%2B3%29%5E2
highlight_green%2845%2F4=%28x-2%29%5E2%2B%28y%2B3%29%5E2%29, which is the equation of a circle.

You also want the line containing points E and F.
Using slope-intercept form completely, y=mx+b, b=y-mx,
m=%282%2B2%29%2F%28-2%29=-2+;
b=-3-%28-2%292=1;
highlight_green%28y=-2x%2B1%29

The rest of the solution process is undone intentionally, so you could finish, or try to finish.