Question 85231: Please help me i am really confused
Line through the point (6,5)
and parallel to the line 2x+3y=7 Found 2 solutions by Lacey020991, ganit:Answer by Lacey020991(49) (Show Source):
You can put this solution on YOUR website! The equation of a line is y = mx+b
If two lines are parallel, they have the same slope.
1) change the given line to y = form.
2x + 3y = 7
3y = -2x + 7
y = x +
So your slope is
2) Next you have the y and x of the equation. You plug these into the y = form to find b, your y-intercept.
5 = *6 + b
5 = -4 + b
9 = b
Now you have you slope, m, and your y-int, b, your ready to write your equation
y = x + 9
You can put this solution on YOUR website! The slopes of parallel lines is always equal.
In the equation 2x + 3y = 7 let us find the slope
3y = 7-2x
y = 7/3 -2/3 x
Now the equation is in the form y = mx +c
where m= ,slope which is the coefficient of x
so we get m= -2/3
We'll use m=-2/3 & the coordinates (6,5) to get the equation of the line.
(since the line goes through the point (6,5) the values of x & y will satisfy the equation. )
y = mx + c
5 = -2/3 * 6 + c
5 = -4 + c
9 = c
The eq of the line becomes
y = -2/3 + 9
Multiplying by 3 on both sides
3y = -2x + 27
3y +2x = 27
the answer is : 3y + 2x = 27
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