SOLUTION: The base of an isosceles triangle is 11 in. less than the length of the equal sides. If the perimeter of the triangle is 37 in., find the length of each of the sides.
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Question 77236: The base of an isosceles triangle is 11 in. less than the length of the equal sides. If the perimeter of the triangle is 37 in., find the length of each of the sides. Answer by rajagopalan(174) (Show Source):
You can put this solution on YOUR website! Let the length of each the equal sides = x
The base of an isosceles triangle is 11 in. less than that = x-11
Side 1 =x
Side2=x
Side3=x-11
Add all=perimeter=3x-11
Perimeter of the triangle is 37 in
So the length of each of the sides is calculated like this:
3x-11=37
3x=37+11
3x=48
x=48/3
x=16
okay
good day
