SOLUTION: John's home is at the point (7,5)and his school is at the point (4,1). Find the distance between the school and home.

Algebra ->  Length-and-distance -> SOLUTION: John's home is at the point (7,5)and his school is at the point (4,1). Find the distance between the school and home.      Log On


   



Question 764265: John's home is at the point (7,5)and his school is at the point (4,1). Find the distance between the school and home.
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Distance Formula:-
Square root (x2-x1)^2 + (y2-y1)^2
Square root (4 - 7)^2 + (1 - 5)^2
Square root (-3)^2 + (-4)^2
Square root 9 + 16
= sqrt%2825%29
= 5
Hope this helps.
:-)