SOLUTION: Indicate the equation of the given line in standard form. The line containing the median of the trapezoid whose vertices are R(-1, 5) , S(1, 8), T(7, -2), and U(2, 0).

Algebra ->  Length-and-distance -> SOLUTION: Indicate the equation of the given line in standard form. The line containing the median of the trapezoid whose vertices are R(-1, 5) , S(1, 8), T(7, -2), and U(2, 0).      Log On


   



Question 742526: Indicate the equation of the given line in standard form.
The line containing the median of the trapezoid whose vertices are R(-1, 5) , S(1, 8), T(7, -2), and U(2, 0).

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

first draw the median of the trapezoid; find endpoints:
Solved by pluggable solver: Midpoint


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (-1, 5), we can say (x1, y1) = (-1, 5)
So x%5B1%5D+=+-1, y%5B1%5D+=+5


Since the second point is (1, 8), we can also say (x2, y2) = (1, 8)
So x%5B2%5D+=+1, y%5B2%5D+=+8


Put this all together to get: x%5B1%5D+=+-1, y%5B1%5D+=+5, x%5B2%5D+=+1, and y%5B2%5D+=+8

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Finding the x coordinate of the midpoint: Add up the corresponding x coordinates x1 and x2 and divide that sum by 2


X Coordinate of Midpoint = %28x%5B1%5D%2Bx%5B2%5D%29%2F2


X Coordinate of Midpoint = %28-1%2B1%29%2F2


X Coordinate of Midpoint = 0%2F2


X Coordinate of Midpoint = 0



So the x coordinate of the midpoint is 0


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Finding the y coordinate of the midpoint: Add up the corresponding y coordinates y1 and y2 and divide that sum by 2


Y Coordinate of Midpoint = %28y%5B1%5D%2By%5B2%5D%29%2F2


Y Coordinate of Midpoint = %285%2B8%29%2F2


Y Coordinate of Midpoint = 13%2F2


Y Coordinate of Midpoint = 6.5


So the y coordinate of the midpoint is 6.5



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Summary:


The midpoint of the segment joining the two points (-1, 5) and (1, 8) is (0, 6.5).


So the answer is (0, 6.5)




Solved by pluggable solver: Midpoint


The first point is (x1,y1). The second point is (x2,y2)


Since the first point is (2, 0), we can say (x1, y1) = (2, 0)
So x%5B1%5D+=+2, y%5B1%5D+=+0


Since the second point is (7, -2), we can also say (x2, y2) = (7, -2)
So x%5B2%5D+=+7, y%5B2%5D+=+-2


Put this all together to get: x%5B1%5D+=+2, y%5B1%5D+=+0, x%5B2%5D+=+7, and y%5B2%5D+=+-2

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Finding the x coordinate of the midpoint: Add up the corresponding x coordinates x1 and x2 and divide that sum by 2


X Coordinate of Midpoint = %28x%5B1%5D%2Bx%5B2%5D%29%2F2


X Coordinate of Midpoint = %282%2B7%29%2F2


X Coordinate of Midpoint = 9%2F2


X Coordinate of Midpoint = 4.5



So the x coordinate of the midpoint is 4.5


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Finding the y coordinate of the midpoint: Add up the corresponding y coordinates y1 and y2 and divide that sum by 2


Y Coordinate of Midpoint = %28y%5B1%5D%2By%5B2%5D%29%2F2


Y Coordinate of Midpoint = %280%2B-2%29%2F2


Y Coordinate of Midpoint = -2%2F2


Y Coordinate of Midpoint = -1


So the y coordinate of the midpoint is -1



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Summary:


The midpoint of the segment joining the two points (2, 0) and (7, -2) is (4.5, -1).


So the answer is (4.5, -1)




so, endpoints are: (0, 6.5) and (4.5, -1)
now find the equation of a line containing the median of the trapezoid
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0, 6.5) and (x2, y2) = (4.5, -1).
Slope a is .
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -1.66666666666667%2A0+%2Bb+=+6.5. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=6.5--1.66666666666667%2A0+=+6.5.

y=(-1.66666666666667)x + (6.5)

Your graph:





all together:



and, the equation of a line in standard form is: 1.66666666666667x%2By=+6.5