SOLUTION: How do you find asymptotes? For example, y=1/x-2

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Question 678483: How do you find asymptotes?
For example, y=1/x-2

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
In general, the procedure for asymptotes is the following:
-set the denominator equal to zero and solve
the zeroes (if any) are the vertical asymptotes
everything else is the domain
-compare the degrees of the numerator and the denominator
if the degrees are the same, then you have a horizontal asymptote at
y = (numerator's leading coefficient) / (denominator's leading coefficient)

if the denominator's degree is greater (by any margin), then you have a horizontal asymptote at y+=+0 (the x-axis)
if the numerator's degree is greater (by a margin of 1), then you have a slant asymptote which you will find by doing long division

y=1%2F%28x-2%29
The vertical asymptotes (and any restrictions on the domain) come from the zeroes of the denominator, so I'll set the denominator equal to zero and solve.
%28x-2%29=0...=>...x=2.....so, domain is all x+%3C%3E+2+
horizontal asymptote: y+=+0 (the x-axis)

+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+1%2F%28x-2%29%2C0%29+
and you can draw a line parallel to y-axis through the point x=2