SOLUTION: Find the exact directed distance from the line 3x-4y=12 to the point (-2,-1).

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Question 639450: Find the exact directed distance from the line 3x-4y=12 to the point (-2,-1).
Found 2 solutions by Edwin McCravy, Alan3354:
Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
Find the exact directed distance from the line 3x-4y=12 to the point (-2,-1).






Use the formula:

The distance from the line Ax+By+C=0 to the point (h,k) is given
by the formula

d = ± where the sign is the sign
of  

For your equation

3x-4y=12, first get 0 on the right:

3x-4y-12=0

Then compare to

Ax+By+C=0

and get A=3, B=-4, C=-12, and (h,k) = (-2,-1), so h=-2 and k=-1

 =  =  which is negative, so the
directed distance will be negative:

Substituting:

d = ±

d = -

d = -

d = -

d = -

d = - = -2.8

And that green line looks a little shorter than 3 units long.
That's only a "ballpark" check. But if you compare it to 3
units along the x-axis or the y-axis, you'll agree that 2.8
is at least close to the length of that green line.

Edwin

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!

Do it like this one:
-------------
Find the exact directed distance from the line 4x+3y=5 to the point (2,-5).
-----------------
It's the distance from the point perpendicular to the line.
---
Find the slope of the line
4x+3y=5
y = (-4/3)x + 5/3
Slope m = -4/3
The slope of lines perpendicular is the negative inverse = 3/4
---
Find the eqn of the perpendicular line thru the point
Use y = mx + b and the point to find b
-5 = (3/4)*2 + b
b = -13/2
--> y = (3/4)x - 7/2 thru the point perpendicular to the given line
Find the intersection of the 2 lines by solving for x & y of the system
y = (3/4)x - 13/2
y = (-4/3)x + 5/3
-----
(-4/3)x + 5/3 = (3/4)x - 13/2
-16x + 20 = 9x - 78
x = 98/25
---------
y = -89/25
------------------
Get the distance between the 2 points


d = 12/5 = 2.4 units

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