SOLUTION: The length of a rectangle is 7yards more than twice its width. Find the dimensions of the rectangle if the area of the rectangle is 39 square yards.

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Question 602974: The length of a rectangle is 7yards more than twice its width. Find the dimensions of the rectangle if the area of the rectangle is 39 square yards.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Let x and (2x+7)represent the width and length respectively

Question states***

 x(2x+7) = 39 yds^2

 2x^2 + 7x - 39 = 0 

 (2x + 13)(x-3) = 0 

   x = 3   |throwing out the Negative solution

Width = 3 yds and length = 13 yds

CHECKING our Answer***

 3yds*13yds = 39 yds^2