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Question 167516: I need an linear equation that is perpendicular to the line y=4x+5 and that passes through the point (0,-3)??
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! I need an linear equation that is perpendicular to the line y=4x+5 and that passes through the point (0,-3)??
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From inspecting:
y=4x+5
we see that the slope is 4
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A line that is perpendicular is a negative reciprocal:
-1/4
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Now, we have a slope (-1/4) and a point (0, -3)
Plug it into the "point slope form":
y - y1 = m(x-x1)
y - (-3) = (-1/4)(x-0)
y + 3 = (-1/4)x
4y + 12 = -x
4y = -x - 12
y = (-1/4)x - 3
y = -x/4 - 3 (This is what they're looking for)
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