SOLUTION: Help please, I am not doing something right. The width of rectangle is fixed at 25cm. What lengths will make the perimiter greater than 92cm. The length must be greater than ? Tha

Algebra ->  Length-and-distance -> SOLUTION: Help please, I am not doing something right. The width of rectangle is fixed at 25cm. What lengths will make the perimiter greater than 92cm. The length must be greater than ? Tha      Log On


   

Question 129463: Help please, I am not doing something right. The width of rectangle is fixed at 25cm. What lengths will make the perimiter greater than 92cm.
The length must be greater than ? Thanks so much for your help.
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
perimeter equals twice the length plus twice the width __ let x=length

2x+2(25)>92 __ 2x+50>92 __ 2x>42 __ x>21