SOLUTION: A vertical pole on a 15° slope is braced by a wire from the top of the pole to a point 20 ft. uphill from the base. If the pole subtends an angle of 62°30' from this point. Find

Algebra ->  Length-and-distance -> SOLUTION: A vertical pole on a 15° slope is braced by a wire from the top of the pole to a point 20 ft. uphill from the base. If the pole subtends an angle of 62°30' from this point. Find       Log On


   



Question 1195042: A vertical pole on a 15° slope is braced by a wire from the top of the pole to a point 20 ft. uphill from the base. If the pole subtends an angle of 62°30' from this point. Find the height of the pole and length of the wire.

Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
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A vertical pole on a 15° slope is braced by a wire from the top of the pole
to a point 20 ft. uphill from the base. If the pole subtends an angle of 62°30'
from this point, find the height of the pole and length of the wire.
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Let point A be the base of the pole;
point B be the upper end of the pole,
and point C be the point where the wire is attached to the slope of the hill.


We have triangle ABC with this given information:

    - angle C is 62°30';

    - angle A is 90° - 15° = 75°;

    - side AC is 20 ft long.


They want you find side c = AB (the pole height) and the side a = BC (the length of the wire).


First, we find the measure of the angle B: it is 180° - 62°30' - 75° = 42°30'.


Next, write sine law proportion

    a%2Fsin%28A%29 = b%2Fsin%28B%29 = c%2Fsin%28C%29.



To find side c = AB, use this part of the proportion

    b%2Fsin%28B%29 = c%2Fsin%28C%29,  b%2Fsin%2842.5%5Eo%29 = c%2Fsin%2862.5%5Eo%29,  20%2F0.67559 = c%2F0.88701,

    which gives  c = %2820%2A0.88701%29%2F0.67559 = 26.26 ft  (the height of the pole).     ANSWER



To find side a = BC, use this part of the proportion

    b%2Fsin%28B%29 = a%2Fsin%28A%29,  b%2Fsin%2842.5%5Eo%29 = a%2Fsin%2875%5Eo%29,  20%2F0.67559 = a%2F0.9659,

    which gives  a = %2820%2A0.9659%29%2F0.67559 = 28.59 ft  (the length of the wire).      ANSWER

Solved.