SOLUTION: https://ibb.co/bz83jGg

Algebra ->  Length-and-distance -> SOLUTION: https://ibb.co/bz83jGg      Log On


   

Question 1188879: https://ibb.co/bz83jGg
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Given,
Angle: 45°
Landing distance: 8.2m
We know, the formula to find the range of a projectile is:
R=%28u%5E2sin%282theta%29%29%2Fg
where, u is the initial velocity, theta is the angle of launch and g+is the gravitational acceleration
substituting the values in the formula, we get:
8.2=%28u%5E2sin%282%2A45%29%29%2F9.8
8.2%2A9.8=u%5E2sin%2890%29.........sin(90)=1
u%5E2=80.36
u=8.964%28m%2Fs%29
Therefore, the takeoff speed is 8.964+%28m%2Fs%29.