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Question 1186272: On a wall, 60 1/2 cm wide, Oscar is going to hang three pictures beside each other, each measuring 9 1/3 cm wide. He will leave 3 1/2 cm in between each pair of adjacent pictures. He plans to use two nails to hang each picture, and will centre these nails leaving 4 cm between each pair. How far, in cm, from the end of the wall(on either side) will the first nail be placed?
Found 2 solutions by CPhill, ikleyn:
Answer by CPhill(1959)   (Show Source):
You can put this solution on YOUR website! Here's how to solve this problem:
**1. Calculate the total width of the pictures:**
* Each picture is 9 1/3 cm wide, which is 9.33 cm in decimal form.
* Three pictures have a total width of 9.33 cm * 3 = 27.99 cm
**2. Calculate the total width of the spaces between pictures:**
* There are two spaces between the three pictures.
* Each space is 3 1/2 cm wide, which is 3.5 cm.
* The total width of the spaces is 3.5 cm * 2 = 7 cm
**3. Calculate the total width of the pictures and spaces:**
* The combined width of the pictures and spaces is 27.99 cm + 7 cm = 34.99 cm
**4. Calculate the remaining space on either side of the wall:**
* The wall is 60 1/2 cm wide, which is 60.5 cm.
* The space left on both sides of the wall is 60.5 cm - 34.99 cm = 25.51 cm
* Since the space is split equally on both sides, each side has 25.51 cm / 2 = 12.755 cm
**5. Calculate the distance from the end of the wall to the first nail:**
* The distance to the first nail is the space on either side plus half the width of a picture plus 4 cm for the nail placement.
* Distance = 12.755 cm + (9.33 cm / 2) + 4 cm
* Distance = 12.755 cm + 4.665 cm + 4 cm
* Distance = 21.42 cm
**Therefore, the first nail will be placed 21.42 cm from the end of the wall.**
Answer by ikleyn(52748)  (Show Source):
You can put this solution on YOUR website! .
On a wall, 60 1/2 cm wide, Oscar is going to hang three pictures beside each other, each measuring 9 1/3 cm wide.
He will leave 3 1/2 cm in between each pair of adjacent pictures. He plans to use two nails to hang each picture,
and will centre these nails leaving 4 cm between each pair. How far, in cm, from the end of the wall(on either side)
will the first nail be placed?
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The solution and the answer in the post by @CPhill are incorrect.
Below is my correct solution.
**1. Calculate the total width of the pictures:**
* Each picture is 9 1/3 cm wide.
* Three pictures have a total width of 9 1/3 cm * 3 = 28 cm
**2. Calculate the total width of the spaces between pictures:**
* There are two spaces between the three pictures.
* Each space is 3 1/2 cm wide.
* The total width of the spaces is 3 1/2 cm * 2 = 7 cm
**3. Calculate the total width of the pictures and spaces:**
* The combined width of the pictures and spaces is 28 cm + 7 cm = 35 cm
**4. Calculate the remaining space on either side of the wall:**
* The wall is 60 1/2 cm wide, which is 60.5 cm.
* The space left on both sides of the wall is 60.5 cm - 35 cm = 25.5 cm
* Since the space is split equally on both sides, each side has 25.5 cm / 2 = 12 3/4 cm
**5. Calculate the distance from the end of the wall to the first nail:**
* The distance to the first nail is the space on either side plus half the width of a picture minus 2 cm
(2 cm is half the space between the nails placement).
* Distance = 12 3/4 cm + (9 1/3 cm / 2) - 2 cm
* Distance = 12 3/4 cm + 4 2/3 cm - 2 cm
* Distance = 15 5/12 cm, or 15.42 cm (rounded decimal)
**Therefore, the first nail will be placed 15 5/12, or 15.42 cm from the end of the wall.**
Solved.
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