SOLUTION: the slope-intercept form of the equation of the line that passes through: (0,-4) and is perpendicular to {{{y = expr(3/2)x + 1}}}.
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-> SOLUTION: the slope-intercept form of the equation of the line that passes through: (0,-4) and is perpendicular to {{{y = expr(3/2)x + 1}}}.
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y = \large -\frac{3}{2} x + 1.
That coding doesn't work on here. But you meant this:
Comparing that to y = mx+b we see that the slope, m = 3/2.
A line perpendicular to it has the slope which is the
reciprocal of that slope with the sign changed.
So the slope of the desired line is m = -2/3
We use the point-slope form, which is:
When we simplify the point-slope form, we will have the
slope-intercept form:
Edwin