SOLUTION: the slope-intercept form of the equation of the line that passes through: (0,-4) and is perpendicular to {{{y = expr(3/2)x + 1}}}.

Algebra ->  Length-and-distance -> SOLUTION: the slope-intercept form of the equation of the line that passes through: (0,-4) and is perpendicular to {{{y = expr(3/2)x + 1}}}.       Log On


   



Question 1184143: the slope-intercept form of the equation of the line that passes through: (0,-4) and is perpendicular to y+=+expr%283%2F2%29x+%2B+1.


Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
y = \large -\frac{3}{2} x + 1. 

That coding doesn't work on here.  But you meant this:

y%22%22=%22%22expr%283%2F2%29x%2B1

Comparing that to y = mx+b we see that the slope, m = 3/2.

A line perpendicular to it has the slope which is the
reciprocal of that slope with the sign changed.

So the slope of the desired line is  m = -2/3

We use the point-slope form, which is:

y-y%5B1%5D%22%22=%22%22m%28x-x%5B1%5D%29

y-%28-4%29%22%22=%22%22expr%28-2%2F3%29%28x-0%29

When we simplify the point-slope form, we will have the
slope-intercept form: 

y%2B4%22%22=%22%22expr%282%2F3%29%28x%29

y%22%22=%22%22expr%282%2F3%29x-4

Edwin