SOLUTION: The radius of the large semicircle is 2cm. What is the radius of the small semicircle? {{{drawing(200,120,-2.5,2.5,-.5,2.5, line(-2,0,2,0),green(line(0,0,0,2)), arc(0,0,4,-4,0,

Algebra ->  Length-and-distance -> SOLUTION: The radius of the large semicircle is 2cm. What is the radius of the small semicircle? {{{drawing(200,120,-2.5,2.5,-.5,2.5, line(-2,0,2,0),green(line(0,0,0,2)), arc(0,0,4,-4,0,      Log On


   



Question 1178916: The radius of the large semicircle is
2cm. What is the radius of the
small semicircle?

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

Let r = the radius of the small semicircle.



For the right triangle:

The red hypotenuse = r+1.
The green right verticle leg = 1.
So, by the Pythagorean theorem, 
the bottom horizontal leg = sqrt%28%28r%2B1%29%5E2-1%5E2%29

We add the two parts of the left horizontal radius of the
large semicircle, and get r%2Bsqrt%28%28r%2B1%29%5E2-1%5E2%29  This 
sum must be equal to the right radius of the large 
semicircle, which is 2.  So we have:

r%2Bsqrt%28%28r%2B1%29%5E2-1%5E2%29%22%22=%22%222

sqrt%28%28r%2B1%29%5E2-1%29%22%22=%22%222-r

sqrt%28r%5E2%2B2r%2B1-1%29%22%22=%22%222-r

sqrt%28r%5E2%2B2r%29%22%22=%22%222-r

Square both sides:

r%5E2%2B2r%22%22=%22%22%282-r%29%5E2

r%5E2%2B2r%22%22=%22%224-4r%2Br%5E2

Subtract r2 from both sides:

2r%22%22=%22%224-4r

6r%22%22=%22%224

r%22%22=%22%224%2F6

r%22%22=%22%222%2F3cm.    <---answer

Edwin