SOLUTION: Find all points on the​ x-axis that are 6 units from the point (2,-3).

In a coordinate plane, the points on ​the  x-axis  are the points (x,0) for arbitrary "x".


So, the points you are looking for, satisfy this distance equation


     = 6,

or

     = 36.


Square both sides to get


    (x-2)^2 + 9 = 6^2

    (x-2)^2 = 36 - 9

    (x-2)^2 = 27

    x - 2 =  = +/- 


Hence, there are two values for x   =   and   = .


So, the points are  A = (,0)  and  B = (,0).     ANSWER