SOLUTION: Find all points having an​ x-coordinate of 1 whose distance from the point (-3,-2) is 5

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Question 1164768: Find all points having an​ x-coordinate of 1 whose distance from the point (-3,-2) is 5
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
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In a coordinate plane, the points having an​ x-coordinate of 1 are the points (1,y) for arbitrary "y".


So, the points you are looking for, satisfy this distance equation


    sqrt%28%28%28-3%29-1%29%5E2+%2B+%28-2%29-y%29%5E2%29 = 5,

or

    sqrt%2816+%2B+%28y%2B2%29%5E2%29 = 5.


Square both sides to get


    16 + (y+2)^2 = 5^2

    (y+2)^2 = 25 - 16

    (y+2)^2 = 9

    y + 2 = sqrt%289%29 = +/- 3


Hence, there are two values for y  y%5B1%5D = 3 - 2 = 1  and  y%5B2%5D = -3 - 2 = -5.


So, the points are  A = (1,1)  and  B = (1,-5).     ANSWER

Solved.