SOLUTION: if the perimeter of a rectangle is 48, then the length is 20 and the width is 4.Find the counterexample of the length and width

Algebra ->  Length-and-distance -> SOLUTION: if the perimeter of a rectangle is 48, then the length is 20 and the width is 4.Find the counterexample of the length and width      Log On


   



Question 1151502: if the perimeter of a rectangle is 48, then the length is 20 and the width is 4.Find the counterexample of the length and width
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

if the perimeter of a rectangle is 48, means
2%28a%2Bb%29=48
a%2Bb=24
so, one example is the length is 20 and the width is 4
There are lots of counterexamples:
the counterexample of the length and width:
the length is 23 and the width is 1
the length is 22 and the width is 2
the length is 21 and the width is 3
the length is 19 and the width is 5
the length is 18 and the width is 6
the length is 17+and the width is 7
the length is 16 and the width is 8
the length is 15+and the width is 9
the length is 14 and the width is 10
the length is 13 and the width is 11
the length is 12 and the width is 12
and vice versa

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if the perimeter of a rectangle is 48, then the length is 20 and the width is 4.Find the counterexample of the length and width
============
Any width number W, where
0 < W < 24
L = 24 - W
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eg, pi and 24-pi
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Those are examples, not sure if they're "counter" to anything.
Maybe W = 20 & L = 4 is a counterexample?