SOLUTION: What is the equation in standard form of the right bisector of the line segment formed by joining points. A (-2,5) B (6,3)

Algebra ->  Length-and-distance -> SOLUTION: What is the equation in standard form of the right bisector of the line segment formed by joining points. A (-2,5) B (6,3)      Log On


   

Question 1137648: What is the equation in standard form of the right bisector of the line segment formed by joining points. A (-2,5) B (6,3)
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
slope of AB
%283-5%29%2F%286-%28-2%29%29
-2%2F8
-1%2F4

slope for line perpendicular to AB
4

bisector is at midpoint of A and B.
x=%28-2%2B6%29%2F2=2
-
y=%285%2B3%29%2F2=4


PERPENDICULAR Bisector to AB
y-4=4%28x-2%29 point_slope_form
y-4=4x-8
4x-8=y-4
4x-y=-4%2B8
highlight%284x-y=4%29