SOLUTION: M is the midpoint of line segment AB. If AM=2x^2+16, AB=6x^2,find AB.

Algebra ->  Length-and-distance -> SOLUTION: M is the midpoint of line segment AB. If AM=2x^2+16, AB=6x^2,find AB.      Log On


   

Question 1121501: M is the midpoint of line segment AB. If AM=2x^2+16, AB=6x^2,find AB.
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
2*|AM| = |AB|     (the lengths)


2*(2x^2+16) = 6x^2


4x^2 + 32 = 6x^2


32 = 2x^2


x^2 = 32/2 = 16


x = sqrt%2816%29 = 4.


|AB| = 6%2A4%5E2 = 6*16 = 96.

Solved.