SOLUTION: Find the equation of a circle passing through the point (1,2) and tangent to both coordinates axes. Pls help me !!!!!

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Question 1106620: Find the equation of a circle passing through the point (1,2) and tangent to both coordinates axes.

Pls help me !!!!!
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

The equation of a circle with center at (h,k) and radius r is:
++%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2+

Since the circle is tangent to the coordinate axes, its center is at (r,r):
+%28x-r%29%5E2+%2B+%28y-r%29%5E2+=+r%5E2+

Plugging in (x=1, y=2):
++%281-r%29%5E2+%2B+%282-r%29%5E2+=+r%5E2+
….
Can you solve it from here? (there are two solutions)