SOLUTION: Find the point on the y-axis equidistant from (-5,2) and (9,-2)

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Question 1087545: Find the point on the y-axis equidistant from (-5,2) and (9,-2)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let that point be (x,y).
Using the distance formula,
D%5B1%5D=%28x%2B5%29%5E2%2B%28y-2%29%5E2
D%5B2%5D=%28x-9%29%5E2%2B%28y%2B2%29%5E2
D%5B1%5D=D%5B2%5D
so,
%28x%2B5%29%5E2%2B%28y-2%29%5E2=%28x-9%29%5E2%2B%28y%2B2%29%5E2
x%5E2%2B10x%2B25%2By%5E2-4y%2B4=x%5E2-18x%2B81%2By%5E2%2B4y%2B4
10x-4y%2B29=-18x%2B4y%2B85
28x-8y=56
7x-2y=14
You also know that since the point is on the y-axis, y=0
7x=14
x=2
(2,0)